4x+[4-2(x+2)]=2x-4

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Solution for 4x+[4-2(x+2)]=2x-4 equation:


Simplifying
4x + [4 + -2(x + 2)] = 2x + -4

Reorder the terms:
4x + [4 + -2(2 + x)] = 2x + -4
4x + [4 + (2 * -2 + x * -2)] = 2x + -4
4x + [4 + (-4 + -2x)] = 2x + -4

Combine like terms: 4 + -4 = 0
4x + [0 + -2x] = 2x + -4
4x + [-2x] = 2x + -4
4x + [-2x] = 2x + -4

Combine like terms: 4x + [-2x] = 2x
2x = 2x + -4

Reorder the terms:
2x = -4 + 2x

Add '-2x' to each side of the equation.
2x + -2x = -4 + 2x + -2x

Combine like terms: 2x + -2x = 0
0 = -4 + 2x + -2x

Combine like terms: 2x + -2x = 0
0 = -4 + 0
0 = -4

Solving
0 = -4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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